What is (\frac{x+8)/(x^2-64)}{(x-4)/(x^2+x-72)} ?

The solution to (\frac{x+8)/(x^2-64)}{(x-4)/(x^2+x-72)} is (x+9)/(x-4)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

simplify (\frac{x+8)/(x^2-64)}{(x-4)/(x^2+x-72)}

simplify

\frac{\frac{x + 8}{x ^{2} - 64}}{\frac{x - 4}{x ^{2} + x - 72}}

\frac{x + 9}{x - 4}

Solution steps

\frac{\frac{x + 8}{x ^{2} - 64}}{\frac{x - 4}{x ^{2} + x - 72}}

Apply the fraction rule:

\frac{\frac{a}{b}}{\frac{c}{d}} = \frac{a \cdot d}{b \cdot c}

= \frac{( x + 8 ) ( x ^{2} + x - 72 )}{( x ^{2} - 64 ) ( x - 4 )}

Cancel

\frac{( x + 8 ) ( x ^{2} + x - 72 )}{( x ^{2} - 64 ) ( x - 4 )} : \frac{x + 9}{x - 4}

= \frac{x + 9}{x - 4}

7 ab + 4 ab - 3 ab

(7 i) (- 3 i)

2 lo g_{2} (12)

\frac{x ^{4} - 5 x ^{3}}{6 x}

What is (\frac{x+8)/(x^2-64)}{(x-4)/(x^2+x-72)} ?
The solution to (\frac{x+8)/(x^2-64)}{(x-4)/(x^2+x-72)} is (x+9)/(x-4)