What is (3a^2-3bc^2+4bc)-(-8a^2+5bc) ?

The solution to (3a^2-3bc^2+4bc)-(-8a^2+5bc) is 11a^2-3bc^2-bc

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simplify (3a^2-3bc^2+4bc)-(-8a^2+5bc)

simplify

(3 a^{2} - 3 b c^{2} + 4 b c) - (- 8 a^{2} + 5 b c)

11 a^{2} - 3 b c^{2} - b c

Solution steps

(3 a^{2} - 3 b c^{2} + 4 b c) - (- 8 a^{2} + 5 b c)

Apply rule:

(a) = a

(3 a^{2} - 3 b c^{2} + 4 b c) = 3 a^{2} - 3 b c^{2} + 4 b c

= 3 a^{2} - 3 b c^{2} + 4 b c - (- 8 a^{2} + 5 b c)

Apply the distributive law:

- (- a + b) = a - b

- (- 8 a^{2} + 5 b c) = 8 a^{2} - 5 b c

= 3 a^{2} - 3 b c^{2} + 4 b c + 8 a^{2} - 5 b c

Group like terms

= 3 a^{2} + 8 a^{2} - 3 b c^{2} + 4 b c - 5 b c

Add similar elements:

3 a^{2} + 8 a^{2} = 11 a^{2}

= 11 a^{2} - 3 b c^{2} + 4 b c - 5 b c

Add similar elements:

4 b c - 5 b c = - b c

= 11 a^{2} - 3 b c^{2} - b c

(y + 11)^{2}

ln (\frac{1}{e ^{12}})

\frac{1}{4 - 2 2}

- 4 x + 3 y + x - 2 z + 2 y

What is (3a^2-3bc^2+4bc)-(-8a^2+5bc) ?
The solution to (3a^2-3bc^2+4bc)-(-8a^2+5bc) is 11a^2-3bc^2-bc