What is (3ab+3a)/(b^3+b^2) ?

The solution to (3ab+3a)/(b^3+b^2) is (3a)/(b^2)

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simplify (3ab+3a)/(b^3+b^2)

simplify

\frac{3 ab + 3 a}{b ^{3} + b ^{2}}

\frac{3 a}{b ^{2}}

Solution steps

\frac{3 ab + 3 a}{b ^{3} + b ^{2}}

Factor out common term

3 a

= \frac{3 a ( b + 1 )}{b ^{3} + b ^{2}}

Factor

b^{3} + b^{2} : b^{2} (b + 1)

= \frac{3 a ( b + 1 )}{b ^{2} ( b + 1 )}

Cancel the common factor:

b + 1

= \frac{3 a}{b ^{2}}

lo g_{4} (4^{6})

\frac{7}{3} + \frac{2}{5}

150 \div 30

(\frac{1}{2} x + 4)^{2}

(5 a + 3 b) (3 a - 5 b)