What is (\frac{x^2-4)/(x^2-11x+18)}{(6x)/(x-9)} ?

The solution to (\frac{x^2-4)/(x^2-11x+18)}{(6x)/(x-9)} is (x+2)/(6x)

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simplify (\frac{x^2-4)/(x^2-11x+18)}{(6x)/(x-9)}

simplify

\frac{\frac{x ^{2} - 4}{x ^{2} - 11 x + 18}}{\frac{6 x}{x - 9}}

\frac{x + 2}{6 x}

Solution steps

\frac{\frac{x ^{2} - 4}{x ^{2} - 11 x + 18}}{\frac{6 x}{x - 9}}

Apply the fraction rule:

\frac{\frac{a}{b}}{\frac{c}{d}} = \frac{a \cdot d}{b \cdot c}

= \frac{( x ^{2} - 4 ) ( x - 9 )}{( x ^{2} - 11 x + 18 ) \cdot 6 x}

Cancel

\frac{( x ^{2} - 4 ) ( x - 9 )}{( x ^{2} - 11 x + 18 ) \cdot 6 x} : \frac{x + 2}{6 x}

= \frac{x + 2}{6 x}

(3 - y)^{3}

4 (- 6)

4 (4 x)

(5 + a)^{2}

What is (\frac{x^2-4)/(x^2-11x+18)}{(6x)/(x-9)} ?
The solution to (\frac{x^2-4)/(x^2-11x+18)}{(6x)/(x-9)} is (x+2)/(6x)