What is (16x^4-8x^2)/(4x) ?

The solution to (16x^4-8x^2)/(4x) is 2x(2x^2-1)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

simplify (16x^4-8x^2)/(4x)

simplify

\frac{16 x ^{4} - 8 x ^{2}}{4 x}

2 x (2 x^{2} - 1)

Solution steps

\frac{16 x ^{4} - 8 x ^{2}}{4 x}

Factor

16 x^{4} - 8 x^{2} : 8 x^{2} (2 x^{2} - 1)

= \frac{8 x ^{2} ( 2 x ^{2} - 1 )}{4 x}

Factor the number:

8 = 4 \cdot 2

= \frac{4 \cdot 2 x ^{2} ( 2 x ^{2} - 1 )}{4 x}

Cancel the common factor:

4

= \frac{2 x ^{2} ( 2 x ^{2} - 1 )}{x}

Apply exponent rule:

a^{b + c} = a^{b} \cdot a^{c}

x^{2} = xx

= \frac{2 xx ( 2 x ^{2} - 1 )}{x}

Cancel the common factor:

x

= 2 x (2 x^{2} - 1)

cot (x) sin (x) + tan (x) cos (x) - cos (x)

\frac{1}{3} \times 5

\frac{3 n - m ^{2} n + 2 n}{6 m}

(7 p^{2} - 9 q^{3})^{2}