What is (x^2-3)-(-7x^2+4x+2) ?

The solution to (x^2-3)-(-7x^2+4x+2) is 8x^2-4x-5

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simplify (x^2-3)-(-7x^2+4x+2)

simplify

(x^{2} - 3) - (- 7 x^{2} + 4 x + 2)

8 x^{2} - 4 x - 5

Solution steps

(x^{2} - 3) - (- 7 x^{2} + 4 x + 2)

Apply rule:

(a) = a

(x^{2} - 3) = x^{2} - 3

= x^{2} - 3 - (- 7 x^{2} + 4 x + 2)

Apply the distributive law:

- (- a + b) = a - b

- (- 7 x^{2} + 4 x + 2) = 7 x^{2} - 4 x - 2

= x^{2} - 3 + 7 x^{2} - 4 x - 2

Group like terms

= x^{2} + 7 x^{2} - 4 x - 3 - 2

Add similar elements:

x^{2} + 7 x^{2} = 8 x^{2}

= 8 x^{2} - 4 x - 3 - 2

Subtract the numbers:

- 3 - 2 = - 5

= 8 x^{2} - 4 x - 5

\frac{30}{25}

(- 4 r^{3}) (- 5 r^{3})

(a - b)^{3}

- lo g_{2} (\frac{1}{2})

\frac{2 x + 10}{x + 5}

What is (x^2-3)-(-7x^2+4x+2) ?
The solution to (x^2-3)-(-7x^2+4x+2) is 8x^2-4x-5