What is 1/(log_{2)(9)}+1/(log_{5)(9)} ?

The solution to 1/(log_{2)(9)}+1/(log_{5)(9)} is 1/(2log_{2)(3)}+1/(2log_{5)(3)}

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simplify 1/(log_{2)(9)}+1/(log_{5)(9)}

simplify

\frac{1}{lo g _{2} ( 9 )} + \frac{1}{lo g _{5} ( 9 )}

\frac{1}{2 lo g _{2} ( 3 )} + \frac{1}{2 lo g _{5} ( 3 )}

Decimal Notation

1.04795 \dots

Solution steps

\frac{1}{lo g _{2} ( 9 )} + \frac{1}{lo g _{5} ( 9 )}

\frac{1}{lo g _{2} ( 9 )} = \frac{1}{2 lo g _{2} ( 3 )}

\frac{1}{lo g _{5} ( 9 )} = \frac{1}{2 lo g _{5} ( 3 )}

= \frac{1}{2 lo g _{2} ( 3 )} + \frac{1}{2 lo g _{5} ( 3 )}

(3 x^{4} - y^{5})^{2}

\frac{4}{2} + 1

lo g_{25} (5)

F (x)

4^{2} - 2^{2}

What is 1/(log_{2)(9)}+1/(log_{5)(9)} ?
The solution to 1/(log_{2)(9)}+1/(log_{5)(9)} is 1/(2log_{2)(3)}+1/(2log_{5)(3)}