What is 16x^6-2x^3y^2+(y^4)/(16) ?

The solution to 16x^6-2x^3y^2+(y^4)/(16) is (256x^6-32x^3y^2+y^4)/(16)

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simplify 16x^6-2x^3y^2+(y^4)/(16)

simplify

16 x^{6} - 2 x^{3} y^{2} + \frac{y ^{4}}{16}

\frac{256 x ^{6} - 32 x ^{3} y ^{2} + y ^{4}}{16}

Solution steps

16 x^{6} - 2 x^{3} y^{2} + \frac{y ^{4}}{16}

Convert

16 x^{6}

to fraction

: \frac{256 x ^{6}}{16}

Convert

2 x^{3} y^{2}

to fraction

: \frac{32 x ^{3} y ^{2}}{16}

= \frac{256 x ^{6}}{16} - \frac{32 x ^{3} y ^{2}}{16} + \frac{y ^{4}}{16}

Apply the fraction rule:

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{256 x ^{6} - 32 x ^{3} y ^{2} + y ^{4}}{16}

\frac{3 ^{8} \cdot ( 4 ^{2} ) ^{4}}{1 2 ^{7}}

\frac{6 x}{x ^{2}}

- 36 + - 72 - 1 + - 162

4 (x + 7)

(3 x^{2} + 5 x - 6) (8 x^{2} - 3 x + 4)

What is 16x^6-2x^3y^2+(y^4)/(16) ?
The solution to 16x^6-2x^3y^2+(y^4)/(16) is (256x^6-32x^3y^2+y^4)/(16)