What is (-2/3 x^2y)^3*(-3/4 xy^2)^2 ?

The solution to (-2/3 x^2y)^3*(-3/4 xy^2)^2 is -(x^8y^7)/6

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simplify (-2/3 x^2y)^3*(-3/4 xy^2)^2

simplify

(- \frac{2}{3} x^{2} y)^{3} \cdot (- \frac{3}{4} x y^{2})^{2}

- \frac{x ^{8} y ^{7}}{6}

Solution steps

(- \frac{2}{3} x^{2} y)^{3} (- \frac{3}{4} x y^{2})^{2}

Simplify

(- \frac{2}{3} x^{2} y)^{3} : - \frac{8 x ^{6} y ^{3}}{27}

= - \frac{8 x ^{6} y ^{3}}{27} (- \frac{3}{4} x y^{2})^{2}

Simplify

(- \frac{3}{4} x y^{2})^{2} : \frac{9 x ^{2} y ^{4}}{16}

= - \frac{8 x ^{6} y ^{3}}{27} \cdot \frac{9 x ^{2} y ^{4}}{16}

Apply the fraction rule:

\frac{a}{b} \cdot \frac{c}{d} = \frac{a \cdot c}{b \cdot d}

= - \frac{8 x ^{6} y ^{3} \cdot 9 x ^{2} y ^{4}}{27 \cdot 16}

Cancel

- \frac{8 x ^{6} y ^{3} \cdot 9 x ^{2} y ^{4}}{27 \cdot 16} : - \frac{x ^{6} y ^{3} x ^{2} y ^{4}}{3 \cdot 2}

= - \frac{x ^{6} y ^{3} x ^{2} y ^{4}}{3 \cdot 2}

Simplify

x^{6} y^{3} x^{2} y^{4} : x^{8} y^{7}

= - \frac{x ^{8} y ^{7}}{3 \cdot 2}

Multiply the numbers:

3 \cdot 2 = 6

= - \frac{x ^{8} y ^{7}}{6}

125 x^{2}

x^{3} - x^{2} - x + 10

\frac{1}{2 + 3} + \frac{1}{2 - 3}

lo g_{\frac{1}{2}} (\frac{1}{5})

lo g_{3} (9^{2} \cdot 7^{4})

What is (-2/3 x^2y)^3*(-3/4 xy^2)^2 ?
The solution to (-2/3 x^2y)^3*(-3/4 xy^2)^2 is -(x^8y^7)/6