What are the solutions to the equation (9f-4)(-8f+7)=0 ?

The solutions to the equation (9f-4)(-8f+7)=0 are f= 4/9 ,f= 7/8

Find the zeros of (9f-4)(-8f+7)=0

The zeros of (9f-4)(-8f+7)=0 are f= 4/9 ,f= 7/8

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(9 f - 4) (- 8 f + 7) = 0

f = \frac{4}{9}, f = \frac{7}{8}

Solution steps

(9 f - 4) (- 8 f + 7) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

9 f - 4 = 0 or - 8 f + 7 = 0

Solve

9 f - 4 = 0 : f = \frac{4}{9}

Solve

- 8 f + 7 = 0 : f = \frac{7}{8}

The solutions to the quadratic equation are:

f = \frac{4}{9}, f = \frac{7}{8}

10 a^{2} b^{3} c^{4} - 15 a^{4} b^{2} c^{4} + 30 a^{4} b^{3} c^{2}

4 x - 8 \geq 12

\frac{2}{7} + \frac{1}{8} + \frac{3}{14}

3 n - 5 \leq 4 n + 3

6 x^{2} - x - 2 = 0

What are the solutions to the equation (9f-4)(-8f+7)=0 ?
The solutions to the equation (9f-4)(-8f+7)=0 are f= 4/9 ,f= 7/8
Find the zeros of (9f-4)(-8f+7)=0
The zeros of (9f-4)(-8f+7)=0 are f= 4/9 ,f= 7/8