What is 6/(x^2-9x+20)*(5x-25)/(3x-6) ?

The solution to 6/(x^2-9x+20)*(5x-25)/(3x-6) is (10)/((x-4)(x-2))

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simplify 6/(x^2-9x+20)*(5x-25)/(3x-6)

simplify

\frac{6}{x ^{2} - 9 x + 20} \cdot \frac{5 x - 25}{3 x - 6}

\frac{10}{( x - 4 ) ( x - 2 )}

Solution steps

\frac{6}{x ^{2} - 9 x + 20} \cdot \frac{5 x - 25}{3 x - 6}

Apply the fraction rule:

\frac{a}{b} \cdot \frac{c}{d} = \frac{a \cdot c}{b \cdot d}

= \frac{6 ( 5 x - 25 )}{( x ^{2} - 9 x + 20 ) ( 3 x - 6 )}

Factor

3 x - 6 : 3 (x - 2)

= \frac{6 ( 5 x - 25 )}{( x ^{2} - 9 x + 20 ) \cdot 3 ( x - 2 )}

Factor the number:

6 = 3 \cdot 2

= \frac{3 \cdot 2 ( 5 x - 25 )}{( x ^{2} - 9 x + 20 ) \cdot 3 ( x - 2 )}

Cancel the common factor:

3

= \frac{2 ( 5 x - 25 )}{( x ^{2} - 9 x + 20 ) ( x - 2 )}

Factor

5 x - 25 : 5 (x - 5)

= \frac{2 \cdot 5 ( x - 5 )}{( x ^{2} - 9 x + 20 ) ( x - 2 )}

Factor

x^{2} - 9 x + 20 : (x - 4) (x - 5)

= \frac{2 \cdot 5 ( x - 5 )}{( x - 4 ) ( x - 5 ) ( x - 2 )}

Cancel the common factor:

x - 5

= \frac{2 \cdot 5}{( x - 4 ) ( x - 2 )}

Multiply the numbers:

2 \cdot 5 = 10

= \frac{10}{( x - 4 ) ( x - 2 )}

\frac{5}{24}

3 \frac{1}{4} + 2 \frac{3}{5} + \frac{5}{12}

2 x \cdot 5

lo g_{0.1} (1000)

\frac{36}{42}

What is 6/(x^2-9x+20)*(5x-25)/(3x-6) ?
The solution to 6/(x^2-9x+20)*(5x-25)/(3x-6) is (10)/((x-4)(x-2))