What is 3(a^2+2ab+b^2) ?

The solution to 3(a^2+2ab+b^2) is 3a^2+6ab+3b^2

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simplify 3(a^2+2ab+b^2)

simplify

3 (a^{2} + 2 ab + b^{2})

3 a^{2} + 6 ab + 3 b^{2}

Solution steps

3 (a^{2} + 2 ab + b^{2})

Apply the distributive law:

m (a + b + c) = ma + mb + m c

3 (a^{2} + 2 ab + b^{2}) = 3 a^{2} + 3 \cdot 2 ab + 3 b^{2}

= 3 a^{2} + 3 \cdot 2 ab + 3 b^{2}

Multiply the numbers:

3 \cdot 2 = 6

= 3 a^{2} + 6 ab + 3 b^{2}

- 15 \cdot - 10

\frac{x + 1}{x ^{2} + 3 x + 2}

2 - 32

\frac{n !}{( n - 3 ) !}

2 + \frac{1}{x}