What is (3/12+7/8 (3/4+2/3))/((-1/3)^3) ?

The solution to (3/12+7/8 (3/4+2/3))/((-1/3)^3) is -1287/32

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simplify (3/12+7/8 (3/4+2/3))/((-1/3)^3)

simplify

\frac{\frac{3}{12} + \frac{7}{8} ( \frac{3}{4} + \frac{2}{3} )}{( - \frac{1}{3} ) ^{3}}

- \frac{1287}{32}

Decimal Notation

- 40.21875

Solution steps

\frac{\frac{3}{12} + \frac{7}{8} ( \frac{3}{4} + \frac{2}{3} )}{( - \frac{1}{3} ) ^{3}}

\frac{3}{12} + \frac{7}{8} (\frac{3}{4} + \frac{2}{3}) = \frac{143}{96}

= \frac{\frac{143}{96}}{( - \frac{1}{3} ) ^{3}}

(- \frac{1}{3})^{3} = - \frac{1}{27}

= \frac{\frac{143}{96}}{- \frac{1}{27}}

Apply the fraction rule:

\frac{a}{- b} = - \frac{a}{b}

= - \frac{\frac{143}{96}}{\frac{1}{27}}

Apply the fraction rule:

\frac{\frac{a}{b}}{\frac{c}{d}} = \frac{a \cdot d}{b \cdot c}

\frac{\frac{143}{96}}{\frac{1}{27}} = \frac{143 \cdot 27}{96 \cdot 1}

= - \frac{143 \cdot 27}{96 \cdot 1}

Cancel

- \frac{143 \cdot 27}{96 \cdot 1} : - \frac{1287}{32}

= - \frac{1287}{32}

- 4 x - 3

(6 x^{2} + 3 y^{2} - 7 x + 4 y - 2) - (2 x^{2} - y^{2} - 7 x + 8)

\frac{( 4 h ^{4} ) ^{4}}{4 h ^{- 8}}

(x^{2} - \frac{1}{2} x)^{2}

\frac{x}{2 x}

What is (3/12+7/8 (3/4+2/3))/((-1/3)^3) ?
The solution to (3/12+7/8 (3/4+2/3))/((-1/3)^3) is -1287/32