What is the domain of f(n)=(4n+24)/(n^2-2n-48) ?

The domain of f(n)=(4n+24)/(n^2-2n-48) is n 8

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domain of f(n)=(4n+24)/(n^2-2n-48)

domain

f (n) = \frac{4 n + 24}{n ^{2} - 2 n - 48}

n < - 6 or - 6 < n < 8 or n > 8

Interval Notation

(- \infty, - 6) \cup (- 6, 8) \cup (8, \infty)

Solution steps

Find undefined (singularity) points:

n = 8, n = - 6

The function domain

n < - 6 or - 6 < n < 8 or n > 8

\frac{\frac{a}{b}}{\frac{c}{b}}

(3 x + 2) (x + 5)

(3 x + 2) (x + 4)

\frac{1}{4 ( - \frac{1}{4 x} )}

\frac{5}{4} - \frac{1}{3} - \frac{1}{2}

What is the domain of f(n)=(4n+24)/(n^2-2n-48) ?
The domain of f(n)=(4n+24)/(n^2-2n-48) is n<-6\lor-6<n<8\lor n>8