What is (x^2+17x+70)/(x^2+6x-40) ?

The solution to (x^2+17x+70)/(x^2+6x-40) is (x+7)/(x-4)

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simplify (x^2+17x+70)/(x^2+6x-40)

simplify

\frac{x ^{2} + 17 x + 70}{x ^{2} + 6 x - 40}

\frac{x + 7}{x - 4}

Solution steps

\frac{x ^{2} + 17 x + 70}{x ^{2} + 6 x - 40}

Factor

x^{2} + 17 x + 70 : (x + 7) (x + 10)

= \frac{( x + 7 ) ( x + 10 )}{x ^{2} + 6 x - 40}

Factor

x^{2} + 6 x - 40 : (x - 4) (x + 10)

= \frac{( x + 7 ) ( x + 10 )}{( x - 4 ) ( x + 10 )}

Cancel the common factor:

x + 10

= \frac{x + 7}{x - 4}

49 d^{2} n - 25 n

∣ 6 - 8 i ∣

(t - 3)^{3}

- x^{2} + 2 x^{2}

(- 2 x) (- 4 x)

What is (x^2+17x+70)/(x^2+6x-40) ?
The solution to (x^2+17x+70)/(x^2+6x-40) is (x+7)/(x-4)