What is (9a^2b^3)/(27a^4b^4c) ?

The solution to (9a^2b^3)/(27a^4b^4c) is 1/(3a^2bc)

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simplify (9a^2b^3)/(27a^4b^4c)

simplify

\frac{9 a ^{2} b ^{3}}{27 a ^{4} b ^{4} c}

\frac{1}{3 a ^{2} b c}

Solution steps

\frac{9 a ^{2} b ^{3}}{27 a ^{4} b ^{4} c}

Factor the number:

27 = 9 \cdot 3

= \frac{9 a ^{2} b ^{3}}{9 \cdot 3 a ^{4} b ^{4} c}

Cancel the common factor:

9

= \frac{a ^{2} b ^{3}}{3 a ^{4} b ^{4} c}

Simplify

\frac{a ^{2}}{a ^{4}} : \frac{1}{a ^{2}}

= \frac{b ^{3}}{3 a ^{2} b ^{4} c}

Simplify

\frac{b ^{3}}{b ^{4}} : \frac{1}{b}

= \frac{1}{3 a ^{2} b c}

\frac{5}{4 - 3 i}

2 (- 6)

\frac{4}{3} + \frac{2}{3}

\frac{1}{6} + \frac{1}{10}

x^{3} - 10 x^{2} + 31 x - 30

What is (9a^2b^3)/(27a^4b^4c) ?
The solution to (9a^2b^3)/(27a^4b^4c) is 1/(3a^2bc)