What is (3+4i)-(2-i) ?

The solution to (3+4i)-(2-i) is 1+5i

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simplify (3+4i)-(2-i)

simplify

(3 + 4 i) - (2 - i)

1 + 5 i

Solution steps

(3 + 4 i) - (2 - i)

Group the real part and the imaginary part of the complex number

(a + bi) - (c + d i) = (a - c) + (b - d) i

= (3 - 2) + (4 - (- 1)) i

Simplify

(3 - 2) + (4 - (- 1)) i : 1 + 5 i

= 1 + 5 i

(x^{2} + 9) (x^{2} - 9)

6 - 6

9 + 4

- lo g_{10} (0.025)

16 - (64)^{\frac{2}{3}}