What is (x^2+2x-8)/(x^2-x-2) ?

The solution to (x^2+2x-8)/(x^2-x-2) is (x+4)/(x+1)

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simplify (x^2+2x-8)/(x^2-x-2)

simplify

\frac{x ^{2} + 2 x - 8}{x ^{2} - x - 2}

\frac{x + 4}{x + 1}

Solution steps

\frac{x ^{2} + 2 x - 8}{x ^{2} - x - 2}

Factor

x^{2} + 2 x - 8 : (x - 2) (x + 4)

= \frac{( x - 2 ) ( x + 4 )}{x ^{2} - x - 2}

Factor

x^{2} - x - 2 : (x + 1) (x - 2)

= \frac{( x - 2 ) ( x + 4 )}{( x + 1 ) ( x - 2 )}

Cancel the common factor:

x - 2

= \frac{x + 4}{x + 1}

(x - 5) (2 x + 3)

- \frac{18}{- 6}

- 121 + - 200 + 9 - - 98

(- 23)^{2}

\frac{( 3 x ^{2} + 2 x - 8 )}{( x + 2 )}

What is (x^2+2x-8)/(x^2-x-2) ?
The solution to (x^2+2x-8)/(x^2-x-2) is (x+4)/(x+1)