What is ((2+tan^2(x)))/(sec^2(x))-1 ?

The solution to ((2+tan^2(x)))/(sec^2(x))-1 is cos^2(x)

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simplify ((2+tan^2(x)))/(sec^2(x))-1

simplify

\frac{( 2 + tan ^{2} ( x ) )}{sec ^{2} ( x )} - 1

cos^{2} (x)

Solution steps

\frac{2 + tan ^{2} ( x )}{sec ^{2} ( x )} - 1

Join

\frac{2 + tan ^{2} ( x )}{sec ^{2} ( x )} - 1 : \frac{1}{sec ^{2} ( x )}

= \frac{1}{sec ^{2} ( x )}

Use the basic trigonometric identity:

\frac{1}{sec ( x )} = cos (x)

= cos^{2} (x)

(2 x y^{3})^{5}

(x^{2} - 2) (x^{2} + 2)

lo g_{10} (3 \frac{x ^{5} z}{y ^{2}})

2 + 9

3 xx

What is ((2+tan^2(x)))/(sec^2(x))-1 ?
The solution to ((2+tan^2(x)))/(sec^2(x))-1 is cos^2(x)