What is factor 2x^3-7x^2+8x-3 ?

The solution to factor 2x^3-7x^2+8x-3 is (x-1)^2(2x-3)

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factor 2x^3-7x^2+8x-3

factor

2 x^{3} - 7 x^{2} + 8 x - 3

(x - 1)^{2} (2 x - 3)

Solution steps

2 x^{3} - 7 x^{2} + 8 x - 3

Use the rational root theorem

= (x - 1) \frac{2 x ^{3} - 7 x ^{2} + 8 x - 3}{x - 1}

\frac{2 x ^{3} - 7 x ^{2} + 8 x - 3}{x - 1} = 2 x^{2} - 5 x + 3

= (x - 1) (2 x^{2} - 5 x + 3)

Factor

2 x^{2} - 5 x + 3 : (x - 1) (2 x - 3)

= (x - 1) (x - 1) (2 x - 3)

Apply exponent rule:

aa = a^{2}

(x - 1) (x - 1) = (x - 1)^{2}

= (x - 1)^{2} (2 x - 3)

2 (5 x + 4) + 3 (2 x - 1)

144 x^{2}

7 w^{2} + 4 w - 6 + w^{2} - 11 w + 13

2 (\frac{1}{2}) + 1

(2 x - 9) (2 x + 9)

What is factor 2x^3-7x^2+8x-3 ?
The solution to factor 2x^3-7x^2+8x-3 is (x-1)^2(2x-3)