What is 1/i+(3+2i)/(2-i) ?

The solution to 1/i+(3+2i)/(2-i) is 4/5+2/5 i

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simplify 1/i+(3+2i)/(2-i)

simplify

\frac{1}{i} + \frac{3 + 2 i}{2 - i}

\frac{4}{5} + \frac{2}{5} i

Solution steps

\frac{1}{i} + \frac{3 + 2 i}{2 - i}

\frac{1}{i} = - i

\frac{3 + 2 i}{2 - i} = \frac{4 + 7 i}{5}

= - i + \frac{4 + 7 i}{5}

Join

- i + \frac{4 + 7 i}{5} : \frac{2 i + 4}{5}

= \frac{2 i + 4}{5}

Rewrite in standard complex form:

\frac{4}{5} + \frac{2}{5} i

= \frac{4}{5} + \frac{2}{5} i

x^{- a}

\frac{- \frac{4}{5}}{- \frac{3}{5}}

- \frac{4}{- 8}

(y^{5})^{2}

(x - 3)^{2} + 6 (x - 1) - x^{2}