What is -8<= (-3x+1)/4 <= 3 ?

The solution to -8<= (-3x+1)/4 <= 3 is -11/3 <= x<= 11

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-8<= (-3x+1)/4 <= 3

- 8 \leq \frac{- 3 x + 1}{4} \leq 3

- \frac{11}{3} \leq x \leq 11

Interval Notation

[- \frac{11}{3}, 11]

Decimal Notation

- 3.66666 \dots \leq x \leq 11

Solution steps

- 8 \leq \frac{- 3 x + 1}{4} \leq 3

a \leq u \leq b

then

a \leq u and u \leq b

- 8 \leq \frac{- 3 x + 1}{4} and \frac{- 3 x + 1}{4} \leq 3

- 8 \leq \frac{- 3 x + 1}{4} : x \leq 11

\frac{- 3 x + 1}{4} \leq 3 : x \geq - \frac{11}{3}

Combine the intervals

x \leq 11 and x \geq - \frac{11}{3}

Merge Overlapping Intervals

- \frac{11}{3} \leq x \leq 11

∣ 2 x - 17 ∣ < - 4

∣ x ∣ - 2 \leq - 3

x + 3 \cdot x + 3

m^{2} + 18 m + 17

\frac{- 10 m ^{2} n}{2 m ^{3} n ^{- 5}}

What is -8<= (-3x+1)/4 <= 3 ?
The solution to -8<= (-3x+1)/4 <= 3 is -11/3 <= x<= 11