What is 1/(x^2)-1/(x^2+x) ?

The solution to 1/(x^2)-1/(x^2+x) is 1/(x^2(x+1))

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simplify 1/(x^2)-1/(x^2+x)

simplify

\frac{1}{x ^{2}} - \frac{1}{x ^{2} + x}

\frac{1}{x ^{2} ( x + 1 )}

Solution steps

\frac{1}{x ^{2}} - \frac{1}{x ^{2} + x}

Least Common Multiplier of

x^{2}, x^{2} + x : x^{2} (x + 1)

Adjust Fractions based on the LCM

= \frac{x + 1}{x ^{2} ( x + 1 )} - \frac{x}{x ^{2} ( x + 1 )}

Apply the fraction rule:

\frac{a}{c} - \frac{b}{c} = \frac{a - b}{c}

= \frac{x + 1 - x}{x ^{2} ( x + 1 )}

Simplify

x + 1 - x : 1

= \frac{1}{x ^{2} ( x + 1 )}

10 \cdot 9 \cdot 8

(5 w)^{2}

\frac{3}{4} \times 5

0 + (- 2)

4 x^{2} - 4 x + 10 + 2 x^{2} + 5 x - 8