What is (x+1+i)(x+1-i) ?

The solution to (x+1+i)(x+1-i) is x^2+2x+2

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simplify (x+1+i)(x+1-i)

simplify

(x + 1 + i) (x + 1 - i)

x^{2} + 2 x + 2

Solution steps

(x + 1 + i) (x + 1 - i)

Rewrite

x + 1 - i

in standard complex form:

(x + 1) - i

= (x + 1 + i) ((x + 1) - i)

Apply complex arithmetic rule:

(a + bi) (a - bi) = a^{2} + b^{2}

= (x + 1)^{2} + 1^{2}

Simplify

(x + 1)^{2} + 1^{2} : x^{2} + 2 x + 2

= x^{2} + 2 x + 2

\frac{2}{20}

\frac{x ^{2} - 16}{x ^{2} - x - 12}

- 5 + (- 9)

6 \cdot 10

(- 3) (312)