What are the solutions to the equation 2x(1+1/2 x)=x(1/2 x+1) ?

The solutions to the equation 2x(1+1/2 x)=x(1/2 x+1) are x=0,x=-2

Find the zeros of 2x(1+1/2 x)=x(1/2 x+1)

The zeros of 2x(1+1/2 x)=x(1/2 x+1) are x=0,x=-2

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2 x (1 + \frac{1}{2} x) = x (\frac{1}{2} x + 1)

x = 0, x = - 2

Solution steps

2 x (1 + \frac{1}{2} x) = x (\frac{1}{2} x + 1)

Move

x (\frac{1}{2} x + 1)

to the left side

2 x (1 + \frac{1}{2} x) - x (\frac{1}{2} x + 1) = 0

Factor

2 x (1 + \frac{1}{2} x) - x (\frac{1}{2} x + 1) : x (\frac{x}{2} + 1)

x (\frac{x}{2} + 1) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x = 0 or \frac{x}{2} + 1 = 0

Solve

\frac{x}{2} + 1 = 0 : x = - 2

The solutions to the quadratic equation are:

x = 0, x = - 2

∣ 2 x + 3 ∣ < 10 ∣ x ∣

\frac{52 !}{( 52 - 7 ) ! 7 !}

8 x - 10

r^{2} + 2 r - 1 = 0

\frac{1}{4} \cdot \frac{1}{2}

What are the solutions to the equation 2x(1+1/2 x)=x(1/2 x+1) ?
The solutions to the equation 2x(1+1/2 x)=x(1/2 x+1) are x=0,x=-2
Find the zeros of 2x(1+1/2 x)=x(1/2 x+1)
The zeros of 2x(1+1/2 x)=x(1/2 x+1) are x=0,x=-2