What is 2/(x^2+x)-3/(x+1) ?

The solution to 2/(x^2+x)-3/(x+1) is (2-3x)/(x(x+1))

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simplify 2/(x^2+x)-3/(x+1)

simplify

\frac{2}{x ^{2} + x} - \frac{3}{x + 1}

\frac{2 - 3 x}{x ( x + 1 )}

Solution steps

\frac{2}{x ^{2} + x} - \frac{3}{x + 1}

Least Common Multiplier of

x^{2} + x, x + 1 : x (x + 1)

Adjust Fractions based on the LCM

= \frac{2}{x ( x + 1 )} - \frac{3 x}{x ( x + 1 )}

Apply the fraction rule:

\frac{a}{c} - \frac{b}{c} = \frac{a - b}{c}

= \frac{2 - 3 x}{x ( x + 1 )}

\frac{5 x ^{3} + 10 x ^{2} - 25 x}{10 x ^{2}}

3 \frac{1}{2} \cdot 4

(x^{3} y^{5})^{4}

\frac{x ^{2}}{64} + \frac{y ^{2}}{9}

\frac{x}{x - 1} - \frac{x}{x + 1}

What is 2/(x^2+x)-3/(x+1) ?
The solution to 2/(x^2+x)-3/(x+1) is (2-3x)/(x(x+1))