What is (4+6i)-(-1+2i) ?

The solution to (4+6i)-(-1+2i) is 5+4i

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simplify (4+6i)-(-1+2i)

simplify

(4 + 6 i) - (- 1 + 2 i)

5 + 4 i

Solution steps

(4 + 6 i) - (- 1 + 2 i)

Group the real part and the imaginary part of the complex number

(a + bi) - (c + d i) = (a - c) + (b - d) i

= (4 - (- 1)) + (6 - 2) i

Simplify

(4 - (- 1)) + (6 - 2) i : 5 + 4 i

= 5 + 4 i

\frac{1}{3 ( 125 ) ^{\frac{2}{3}}}

ln (1.03)

(4 z)^{3}

(1 + x)^{- \frac{1}{2}}

6 (x + 3)