What is (7+4i)-(1+2i) ?

The solution to (7+4i)-(1+2i) is 6+2i

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simplify (7+4i)-(1+2i)

simplify

(7 + 4 i) - (1 + 2 i)

6 + 2 i

Solution steps

(7 + 4 i) - (1 + 2 i)

Group the real part and the imaginary part of the complex number

(a + bi) - (c + d i) = (a - c) + (b - d) i

= (7 - 1) + (4 - 2) i

Simplify

(7 - 1) + (4 - 2) i : 6 + 2 i

= 6 + 2 i

18 x^{3}

2 a^{2} b c - 4 a b^{2} c + 16 ab c^{2}

- \frac{1}{3} \cdot (- 2)

\frac{48}{50}

(x - 5) (x + 10)