What is log_{6}(18)+log_{6}(2) ?

The solution to log_{6}(18)+log_{6}(2) is 2

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simplify log_{6}(18)+log_{6}(2)

simplify

lo g_{6} (18) + lo g_{6} (2)

2

Solution steps

lo g_{6} (18) + lo g_{6} (2)

Apply log rule:

lo g_{a} (x) + lo g_{a} (y) = lo g_{a} (x y)

lo g_{6} (18) + lo g_{6} (2) = lo g_{6} (18 \cdot 2)

= lo g_{6} (18 \cdot 2)

Multiply the numbers:

18 \cdot 2 = 36

= lo g_{6} (36)

Factor the number:

36 = 6^{2}

= lo g_{6} (6^{2})

Apply log rule:

lo g_{a} (a^{b}) = b

= 2

4 \times 15

lo g_{3} (9) - lo g_{3} (3)

z \cdot 30 z^{2} \cdot 35 z^{3}

(- 1)^{1 + 1}

e^{i 0}