What is expand (2x-3)(3x^2-5x-4) ?

The solution to expand (2x-3)(3x^2-5x-4) is 6x^3-19x^2+7x+12

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expand (2x-3)(3x^2-5x-4)

expand

(2 x - 3) (3 x^{2} - 5 x - 4)

6 x^{3} - 19 x^{2} + 7 x + 12

Solution steps

(2 x - 3) (3 x^{2} - 5 x - 4)

Distribute parentheses

= 2 x \cdot 3 x^{2} + 2 x (- 5 x) + 2 x (- 4) - 3 \cdot 3 x^{2} - 3 (- 5 x) - 3 (- 4)

Simplify

2 x \cdot 3 x^{2} + 2 x (- 5 x) + 2 x (- 4) - 3 \cdot 3 x^{2} - 3 (- 5 x) - 3 (- 4) : 6 x^{3} - 19 x^{2} + 7 x + 12

= 6 x^{3} - 19 x^{2} + 7 x + 12

ln ((3 x)^{2 x})

(x + 1) (2 x + 2)

(3 a + 2)^{2}

\frac{1}{1 - sin ( t )} + \frac{1}{1 + sin ( t )}

- 4 x

What is expand (2x-3)(3x^2-5x-4) ?
The solution to expand (2x-3)(3x^2-5x-4) is 6x^3-19x^2+7x+12