What is factor 16x^2+40xy+25y^2 ?

The solution to factor 16x^2+40xy+25y^2 is (4x+5y)^2

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factor 16x^2+40xy+25y^2

factor

16 x^{2} + 40 x y + 25 y^{2}

(4 x + 5 y)^{2}

Solution steps

16 x^{2} + 40 x y + 25 y^{2}

Rewrite in the form of

a^{2} + 2 ab + b^{2} :

16 x^{2} = (4 x)^{2}

25 y^{2} = (5 y)^{2}

40 x y = 2 \cdot 4 x \cdot 5 y

= (4 x)^{2} + 2 \cdot 4 x \cdot 5 y + (5 y)^{2}

Apply Perfect Square Formula:

a^{2} + 2 ab + b^{2} = (a + b)^{2}

(4 x)^{2} + 2 \cdot 4 x \cdot 5 y + (5 y)^{2} = (4 x + 5 y)^{2}

= (4 x + 5 y)^{2}

3012

1 + \frac{1}{s ^{2}}

\frac{18}{66}

- 3 (5 g + 1) + 8 g

- 1 - - 3 + 64 + - 147

What is factor 16x^2+40xy+25y^2 ?
The solution to factor 16x^2+40xy+25y^2 is (4x+5y)^2