What are the solutions to the equation 3x^2+6x=12 ?

The solutions to the equation 3x^2+6x=12 are x=-1+sqrt(5),x=-1-sqrt(5)

Find the zeros of 3x^2+6x=12

The zeros of 3x^2+6x=12 are x=-1+sqrt(5),x=-1-sqrt(5)

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3 x^{2} + 6 x = 12

x = - 1 + 5, x = - 1 - 5

Decimal Notation

x = 1.23606 \dots, x = - 3.23606 \dots

Solution steps

3 x^{2} + 6 x = 12

Move

12

to the left side

3 x^{2} + 6 x - 12 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 \cdot 3 ( - 12 )}{2 \cdot 3}

6^{2} - 4 \cdot 3 (- 12) = 65

x_{1, 2} = \frac{- 6 \pm 6 5}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- 6 + 6 5}{2 \cdot 3}, x_{2} = \frac{- 6 - 6 5}{2 \cdot 3}

x = \frac{- 6 + 6 5}{2 \cdot 3} : - 1 + 5

x = \frac{- 6 - 6 5}{2 \cdot 3} : - 1 - 5

The solutions to the quadratic equation are:

x = - 1 + 5, x = - 1 - 5

36 u^{2} - v^{2}

(\frac{64}{27})^{- \frac{2}{3}}

(x + 3)^{2} - 2 (x + 2)^{2} + (2 x + 3) (2 x + 1) = 0

13 x^{2} - 144 x + 396 = 0

4 x + 11 < - 21

What are the solutions to the equation 3x^2+6x=12 ?
The solutions to the equation 3x^2+6x=12 are x=-1+sqrt(5),x=-1-sqrt(5)
Find the zeros of 3x^2+6x=12
The zeros of 3x^2+6x=12 are x=-1+sqrt(5),x=-1-sqrt(5)