What is (x^2+3x-5)+(-2x^2+4x+1) ?

The solution to (x^2+3x-5)+(-2x^2+4x+1) is -x^2+7x-4

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simplify (x^2+3x-5)+(-2x^2+4x+1)

simplify

(x^{2} + 3 x - 5) + (- 2 x^{2} + 4 x + 1)

- x^{2} + 7 x - 4

Solution steps

(x^{2} + 3 x - 5) + (- 2 x^{2} + 4 x + 1)

Simplify

(x^{2} + 3 x - 5) + (- 2 x^{2} + 4 x + 1) : x^{2} + 3 x - 5 - 2 x^{2} + 4 x + 1

= x^{2} + 3 x - 5 - 2 x^{2} + 4 x + 1

Group like terms

= x^{2} - 2 x^{2} + 3 x + 4 x - 5 + 1

Add similar elements:

x^{2} - 2 x^{2} = - x^{2}

= - x^{2} + 3 x + 4 x - 5 + 1

Add similar elements:

3 x + 4 x = 7 x

= - x^{2} + 7 x - 5 + 1

Add the numbers:

- 5 + 1 = - 4

= - x^{2} + 7 x - 4

25 \times 4

\frac{15 a ^{3} - 5 ab - 10 a ^{2} b ^{2}}{- 5 ab}

\frac{44}{5}

2 \frac{7}{8}

What is (x^2+3x-5)+(-2x^2+4x+1) ?
The solution to (x^2+3x-5)+(-2x^2+4x+1) is -x^2+7x-4