What is (r+1)^2(r-3)(r-1)(r-2i)(r+2i) ?

The solution to (r+1)^2(r-3)(r-1)(r-2i)(r+2i) is (r+1)^2(r-3)(r-1)(r^2+4)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

simplify (r+1)^2(r-3)(r-1)(r-2i)(r+2i)

simplify

(r + 1)^{2} (r - 3) (r - 1) (r - 2 i) (r + 2 i)

(r + 1)^{2} (r - 3) (r - 1) (r^{2} + 4)

Solution steps

(r + 1)^{2} (r - 3) (r - 1) (r - 2 i) (r + 2 i)

Apply complex arithmetic rule:

(a + bi) (a - bi) = a^{2} + b^{2}

= (r + 1)^{2} (r - 3) (r - 1) (r^{2} + (- 2)^{2})

(- 2)^{2} = 4

= (r + 1)^{2} (r - 3) (r - 1) (r^{2} + 4)

(616) (- 49)

\frac{( x ^{2} - 5 x + 4 )}{( x - 4 )}

2 (2 x + 3)

1 4^{- 1}

\frac{1}{8} (16 m - 8) - 17

What is (r+1)^2(r-3)(r-1)(r-2i)(r+2i) ?
The solution to (r+1)^2(r-3)(r-1)(r-2i)(r+2i) is (r+1)^2(r-3)(r-1)(r^2+4)