What is (5x-10)/(x^2-36)*(4x+24)/(x^2+5x-14) ?

The solution to (5x-10)/(x^2-36)*(4x+24)/(x^2+5x-14) is (20)/((x-6)(x+7))

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simplify (5x-10)/(x^2-36)*(4x+24)/(x^2+5x-14)

simplify

\frac{5 x - 10}{x ^{2} - 36} \cdot \frac{4 x + 24}{x ^{2} + 5 x - 14}

\frac{20}{( x - 6 ) ( x + 7 )}

Solution steps

\frac{5 x - 10}{x ^{2} - 36} \cdot \frac{4 x + 24}{x ^{2} + 5 x - 14}

Apply the fraction rule:

\frac{a}{b} \cdot \frac{c}{d} = \frac{a \cdot c}{b \cdot d}

= \frac{( 5 x - 10 ) ( 4 x + 24 )}{( x ^{2} - 36 ) ( x ^{2} + 5 x - 14 )}

Factor

5 x - 10 : 5 (x - 2)

= \frac{5 ( x - 2 ) ( 4 x + 24 )}{( x ^{2} - 36 ) ( x ^{2} + 5 x - 14 )}

Factor

x^{2} + 5 x - 14 : (x - 2) (x + 7)

= \frac{5 ( x - 2 ) ( 4 x + 24 )}{( x ^{2} - 36 ) ( x - 2 ) ( x + 7 )}

Cancel the common factor:

x - 2

= \frac{5 ( 4 x + 24 )}{( x ^{2} - 36 ) ( x + 7 )}

Factor

4 x + 24 : 4 (x + 6)

= \frac{5 \cdot 4 ( x + 6 )}{( x ^{2} - 36 ) ( x + 7 )}

Factor

x^{2} - 36 : (x + 6) (x - 6)

= \frac{5 \cdot 4 ( x + 6 )}{( x + 6 ) ( x - 6 ) ( x + 7 )}

Cancel the common factor:

x + 6

= \frac{5 \cdot 4}{( x - 6 ) ( x + 7 )}

Multiply the numbers:

5 \cdot 4 = 20

= \frac{20}{( x - 6 ) ( x + 7 )}

m (2 a + b) + p (2 a + b)

\frac{32}{25}

\frac{- 5}{- 6}

(x + 3) + 3

(\frac{1}{2} x - 2)^{2}

What is (5x-10)/(x^2-36)*(4x+24)/(x^2+5x-14) ?
The solution to (5x-10)/(x^2-36)*(4x+24)/(x^2+5x-14) is (20)/((x-6)(x+7))