What is expand x(x-1)(x-2)(x-3)(x-4) ?

The solution to expand x(x-1)(x-2)(x-3)(x-4) is x^5-10x^4+35x^3-50x^2+24x

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expand x(x-1)(x-2)(x-3)(x-4)

expand

x (x - 1) (x - 2) (x - 3) (x - 4)

x^{5} - 10 x^{4} + 35 x^{3} - 50 x^{2} + 24 x

Solution steps

x (x - 1) (x - 2) (x - 3) (x - 4)

Expand

x (x - 1) (x - 2) (x - 3) (x - 4) : x (x^{2} - 3 x + 2) (x - 3) (x - 4)

= x (x^{2} - 3 x + 2) (x - 3) (x - 4)

Apply FOIL method

(x - 3) (x - 4) : x^{2} - 7 x + 12

= x (x^{2} - 3 x + 2) (x^{2} - 7 x + 12)

Expand

(x^{2} - 3 x + 2) (x^{2} - 7 x + 12) : x^{4} - 10 x^{3} + 35 x^{2} - 50 x + 24

= x (x^{4} - 10 x^{3} + 35 x^{2} - 50 x + 24)

Distribute parentheses

= x x^{4} + x (- 10 x^{3}) + x \cdot 35 x^{2} + x (- 50 x) + x \cdot 24

Simplify

x x^{4} + x (- 10 x^{3}) + x \cdot 35 x^{2} + x (- 50 x) + x \cdot 24 : x^{5} - 10 x^{4} + 35 x^{3} - 50 x^{2} + 24 x

= x^{5} - 10 x^{4} + 35 x^{3} - 50 x^{2} + 24 x

(4 p^{2})^{3}

3 \cdot \frac{3}{2}

(\frac{3}{2})^{2}

- \frac{4}{6} \times 0.4

(x - 14)^{2}

What is expand x(x-1)(x-2)(x-3)(x-4) ?
The solution to expand x(x-1)(x-2)(x-3)(x-4) is x^5-10x^4+35x^3-50x^2+24x