What is expand (x+1)(x-2)(x-5) ?

The solution to expand (x+1)(x-2)(x-5) is x^3-6x^2+3x+10

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

expand (x+1)(x-2)(x-5)

expand

(x + 1) (x - 2) (x - 5)

x^{3} - 6 x^{2} + 3 x + 10

Solution steps

(x + 1) (x - 2) (x - 5)

Expand

(x + 1) (x - 2) (x - 5) : (x^{2} - x - 2) (x - 5)

= (x^{2} - x - 2) (x - 5)

Distribute parentheses

= x^{2} x + x^{2} (- 5) - xx - x (- 5) - 2 x - 2 (- 5)

Simplify

x^{2} x + x^{2} (- 5) - xx - x (- 5) - 2 x - 2 (- 5) : x^{3} - 6 x^{2} + 3 x + 10

= x^{3} - 6 x^{2} + 3 x + 10

36 x^{2} + 48 x + 16

(3 x + 2) (3 x - 5)

\frac{3}{8} \div \frac{3}{4}

\frac{\frac{x ^{2} - 2 x}{6}}{\frac{3 x - 6}{x}}

ln (e^{\frac{1}{2}})

What is expand (x+1)(x-2)(x-5) ?
The solution to expand (x+1)(x-2)(x-5) is x^3-6x^2+3x+10