What is factor 4x^4-8x^3+12x^2 ?

The solution to factor 4x^4-8x^3+12x^2 is 4x^2(x^2-2x+3)

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factor 4x^4-8x^3+12x^2

factor

4 x^{4} - 8 x^{3} + 12 x^{2}

4 x^{2} (x^{2} - 2 x + 3)

Solution steps

4 x^{4} - 8 x^{3} + 12 x^{2}

Apply exponent rule:

a^{b + c} = a^{b} a^{c}

x^{3} = x x^{2}

= 4 x^{2} x^{2} - 8 x x^{2} + 12 x^{2}

Rewrite

8

4 \cdot 2

Rewrite

12

4 \cdot 3

= 4 x^{2} x^{2} - 4 \cdot 2 x x^{2} + 4 \cdot 3 x^{2}

Factor out common term

4 x^{2}

= 4 x^{2} (x^{2} - 2 x + 3)

(- 5 x y^{2} z) (7 x^{6} y^{2} z - 3 x^{5} y - 4 x z)

f (x) = \frac{x ^{2} - 4 x}{16 - x ^{2}}

32 + 550

(2 a^{2} + 3 b) (2 a^{2} - 3 b)

\frac{x ^{3} - 27 y ^{3}}{x ^{2} - 9 y ^{2}}

What is factor 4x^4-8x^3+12x^2 ?
The solution to factor 4x^4-8x^3+12x^2 is 4x^2(x^2-2x+3)