What is (7+4i)-(8+i) ?

The solution to (7+4i)-(8+i) is -1+3i

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simplify (7+4i)-(8+i)

simplify

(7 + 4 i) - (8 + i)

- 1 + 3 i

Solution steps

(7 + 4 i) - (8 + i)

Group the real part and the imaginary part of the complex number

(a + bi) - (c + d i) = (a - c) + (b - d) i

= (7 - 8) + (4 - 1) i

Simplify

(7 - 8) + (4 - 1) i : - 1 + 3 i

= - 1 + 3 i

16 x^{2} - 4 x

(x^{3}) (x^{- 2})

3 (\frac{3}{2})

83 + 48

(9 - 2 x)^{2}