What are the solutions to the equation 3x^2+5x+7=0 ?

The solutions to the equation 3x^2+5x+7=0 are x=-5/6+i(sqrt(59))/6 ,x=-5/6-i(sqrt(59))/6

Find the zeros of 3x^2+5x+7=0

The zeros of 3x^2+5x+7=0 are x=-5/6+i(sqrt(59))/6 ,x=-5/6-i(sqrt(59))/6

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3 x^{2} + 5 x + 7 = 0

x = - \frac{5}{6} + i \frac{59}{6}, x = - \frac{5}{6} - i \frac{59}{6}

Solution steps

3 x^{2} + 5 x + 7 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 5 \pm 5 ^{2} - 4 \cdot 3 \cdot 7}{2 \cdot 3}

Simplify

5^{2} - 4 \cdot 3 \cdot 7 : 59 i

x_{1, 2} = \frac{- 5 \pm 59 i}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- 5 + 59 i}{2 \cdot 3}, x_{2} = \frac{- 5 - 59 i}{2 \cdot 3}

x = \frac{- 5 + 59 i}{2 \cdot 3} : - \frac{5}{6} + i \frac{59}{6}

x = \frac{- 5 - 59 i}{2 \cdot 3} : - \frac{5}{6} - i \frac{59}{6}

The solutions to the quadratic equation are:

x = - \frac{5}{6} + i \frac{59}{6}, x = - \frac{5}{6} - i \frac{59}{6}

(3 y^{4})^{2}

\frac{1}{- \frac{2}{2}}

∣ 2 x - 5 ∣ + 2 > 5

5 x (x + 6) = - 50

6 - \frac{3}{4} x + \frac{1}{3} = \frac{1}{2} x + 5

What are the solutions to the equation 3x^2+5x+7=0 ?
The solutions to the equation 3x^2+5x+7=0 are x=-5/6+i(sqrt(59))/6 ,x=-5/6-i(sqrt(59))/6
Find the zeros of 3x^2+5x+7=0
The zeros of 3x^2+5x+7=0 are x=-5/6+i(sqrt(59))/6 ,x=-5/6-i(sqrt(59))/6