What is (x^2+5x+4)/(x^2+2x-8) ?

The solution to (x^2+5x+4)/(x^2+2x-8) is (x+1)/(x-2)

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simplify (x^2+5x+4)/(x^2+2x-8)

simplify

\frac{x ^{2} + 5 x + 4}{x ^{2} + 2 x - 8}

\frac{x + 1}{x - 2}

Solution steps

\frac{x ^{2} + 5 x + 4}{x ^{2} + 2 x - 8}

Factor

x^{2} + 5 x + 4 : (x + 1) (x + 4)

= \frac{( x + 1 ) ( x + 4 )}{x ^{2} + 2 x - 8}

Factor

x^{2} + 2 x - 8 : (x - 2) (x + 4)

= \frac{( x + 1 ) ( x + 4 )}{( x - 2 ) ( x + 4 )}

Cancel the common factor:

x + 4

= \frac{x + 1}{x - 2}

3 a^{2} - a^{2}

2 \times \frac{1}{5}

40 x - 35

\frac{25 - v ^{2}}{3 v ^{2} - 13 v - 10}

4 y^{2} x - 2 x^{2} (y + 3) + 5 y x^{2} - 3 x^{2}

What is (x^2+5x+4)/(x^2+2x-8) ?
The solution to (x^2+5x+4)/(x^2+2x-8) is (x+1)/(x-2)