What is (2x^2-2)/(3x^2+6x+3) ?

The solution to (2x^2-2)/(3x^2+6x+3) is (2(x-1))/(3(x+1))

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simplify (2x^2-2)/(3x^2+6x+3)

simplify

\frac{2 x ^{2} - 2}{3 x ^{2} + 6 x + 3}

\frac{2 ( x - 1 )}{3 ( x + 1 )}

Solution steps

\frac{2 x ^{2} - 2}{3 x ^{2} + 6 x + 3}

Factor

2 x^{2} - 2 : 2 (x + 1) (x - 1)

= \frac{2 ( x + 1 ) ( x - 1 )}{3 x ^{2} + 6 x + 3}

Factor

3 x^{2} + 6 x + 3 : 3 (x + 1)^{2}

= \frac{2 ( x + 1 ) ( x - 1 )}{3 ( x + 1 ) ^{2}}

Apply exponent rule:

a^{b + c} = a^{b} \cdot a^{c}

(x + 1)^{2} = (x + 1) (x + 1)

= \frac{2 ( x + 1 ) ( x - 1 )}{3 ( x + 1 ) ( x + 1 )}

Cancel the common factor:

x + 1

= \frac{2 ( x - 1 )}{3 ( x + 1 )}

7 \cdot 49

\frac{7 x - 14}{x ^{2} - 2 x}

(420) (- 6 - 6)

lo g_{\frac{2}{5}} ((\frac{625}{16})^{2})

(4^{x})^{2}

What is (2x^2-2)/(3x^2+6x+3) ?
The solution to (2x^2-2)/(3x^2+6x+3) is (2(x-1))/(3(x+1))