What is ((2x)^{-4})/(x^{-1)*x} ?

The solution to ((2x)^{-4})/(x^{-1)*x} is 1/(16x^4)

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simplify ((2x)^{-4})/(x^{-1)*x}

simplify

\frac{( 2 x ) ^{- 4}}{x ^{- 1} \cdot x}

\frac{1}{16 x ^{4}}

Solution steps

\frac{( 2 x ) ^{- 4}}{x ^{- 1} x}

Simplify

x^{- 1} x : 1

= \frac{( 2 x ) ^{- 4}}{1}

Apply the fraction rule:

\frac{a}{1} = a

= (2 x)^{- 4}

Simplify

(2 x)^{- 4} : \frac{1}{16 x ^{4}}

= \frac{1}{16 x ^{4}}

\frac{x ^{15} + y ^{15}}{x ^{3} + y ^{3}}

(x^{3} - 2 x^{2} + 3 x - 1) (2 x + 3)

\frac{lo g _{10} ( 7 )}{lo g _{10} ( 5 )}

- \frac{2}{2} + 1

lo g_{\frac{1}{2}} (7)

What is ((2x)^{-4})/(x^{-1)*x} ?
The solution to ((2x)^{-4})/(x^{-1)*x} is 1/(16x^4)