What is factor x^3-6x^2+9x-4 ?

The solution to factor x^3-6x^2+9x-4 is (x-1)^2(x-4)

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factor x^3-6x^2+9x-4

factor

x^{3} - 6 x^{2} + 9 x - 4

(x - 1)^{2} (x - 4)

Solution steps

x^{3} - 6 x^{2} + 9 x - 4

Use the rational root theorem

= (x - 1) \frac{x ^{3} - 6 x ^{2} + 9 x - 4}{x - 1}

\frac{x ^{3} - 6 x ^{2} + 9 x - 4}{x - 1} = x^{2} - 5 x + 4

= (x - 1) (x^{2} - 5 x + 4)

Factor

x^{2} - 5 x + 4 : (x - 1) (x - 4)

= (x - 1) (x - 1) (x - 4)

Apply exponent rule:

aa = a^{2}

(x - 1) (x - 1) = (x - 1)^{2}

= (x - 1)^{2} (x - 4)

\frac{6 x ^{2} - 2 y ^{2} - x y}{y + 2 x}

1 - k^{3}

(1 - cos (x)) (1 - cos (x))

(4 x^{3} y^{2} - 5 x^{2} y^{3} + 6 x^{4} y - 8 x y^{4}) - (12 x^{2} y^{3} - 3 x y^{4} + 4 x^{3} y^{2} - 9 x^{4} y)

\frac{1 - - 1}{1 + - 1}

What is factor x^3-6x^2+9x-4 ?
The solution to factor x^3-6x^2+9x-4 is (x-1)^2(x-4)