What is (8-7x-x^2)/(x+8)*(x+5)/(9x-9) ?

The solution to (8-7x-x^2)/(x+8)*(x+5)/(9x-9) is (-x-5)/9

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simplify (8-7x-x^2)/(x+8)*(x+5)/(9x-9)

simplify

\frac{8 - 7 x - x ^{2}}{x + 8} \cdot \frac{x + 5}{9 x - 9}

\frac{- x - 5}{9}

Solution steps

\frac{8 - 7 x - x ^{2}}{x + 8} \cdot \frac{x + 5}{9 x - 9}

Cancel

\frac{8 - 7 x - x ^{2}}{x + 8} : - x + 1

= (- x + 1) \frac{x + 5}{9 x - 9}

Apply the fraction rule:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{( - x + 1 ) ( x + 5 )}{9 x - 9}

Factor

9 x - 9 : 9 (x - 1)

= \frac{( - x + 1 ) ( x + 5 )}{9 ( x - 1 )}

Factor

- x + 1 : - (x - 1)

= \frac{- ( x - 1 ) ( x + 5 )}{9 ( x - 1 )}

Cancel the common factor:

x - 1

= \frac{- ( x + 5 )}{9}

Apply the distributive law:

- (a + b) = - a - b

- (x + 5) = - x - 5

= \frac{- x - 5}{9}

\frac{5}{3 i}

144 + - 8 + 100 - - 2

\frac{1}{x ^{2}} + \frac{1}{x ^{2}}

\frac{x}{5} + \frac{5}{2}

4 (2 g + 3) - 5 (4 g - 4)

What is (8-7x-x^2)/(x+8)*(x+5)/(9x-9) ?
The solution to (8-7x-x^2)/(x+8)*(x+5)/(9x-9) is (-x-5)/9