What is (\frac{3x^2)/(2y^3)}{(9x)/(4y^4)} ?

The solution to (\frac{3x^2)/(2y^3)}{(9x)/(4y^4)} is (2xy)/3

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simplify (\frac{3x^2)/(2y^3)}{(9x)/(4y^4)}

simplify

\frac{\frac{3 x ^{2}}{2 y ^{3}}}{\frac{9 x}{4 y ^{4}}}

\frac{2 x y}{3}

Solution steps

\frac{\frac{3 x ^{2}}{2 y ^{3}}}{\frac{9 x}{4 y ^{4}}}

Apply the fraction rule:

\frac{\frac{a}{b}}{\frac{c}{d}} = \frac{a \cdot d}{b \cdot c}

= \frac{3 x ^{2} \cdot 4 y ^{4}}{2 y ^{3} \cdot 9 x}

Cancel

\frac{3 x ^{2} \cdot 4 y ^{4}}{2 y ^{3} \cdot 9 x} : \frac{x \cdot 2 y}{3}

= \frac{x \cdot 2 y}{3}

= \frac{2 x y}{3}

2.8 - 4.4 n - 2 n + 7

249

1 + 2

\frac{78}{100}

(0.6)^{3}

What is (\frac{3x^2)/(2y^3)}{(9x)/(4y^4)} ?
The solution to (\frac{3x^2)/(2y^3)}{(9x)/(4y^4)} is (2xy)/3