What is ((4s^{-1}j^{-3})^{-3})/(20s^{-2)} ?

The solution to ((4s^{-1}j^{-3})^{-3})/(20s^{-2)} is (s^5j^9)/(1280)

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simplify ((4s^{-1}j^{-3})^{-3})/(20s^{-2)}

simplify

\frac{( 4 s ^{- 1} j ^{- 3} ) ^{- 3}}{20 s ^{- 2}}

\frac{s ^{5} j ^{9}}{1280}

Solution steps

\frac{( 4 s ^{- 1} j ^{- 3} ) ^{- 3}}{20 s ^{- 2}}

Simplify

(4 s^{- 1} j^{- 3})^{- 3} : 4^{- 3} s^{3} j^{9}

= \frac{4 ^{- 3} s ^{3} j ^{9}}{20 s ^{- 2}}

Factor the number:

20 = 4 \cdot 5

= \frac{4 ^{- 3} s ^{3} j ^{9}}{4 \cdot 5 s ^{- 2}}

\frac{4 ^{- 3}}{4} = \frac{1}{4 ^{4}}

= \frac{s ^{3} j ^{9}}{4 ^{4} \cdot 5 s ^{- 2}}

Simplify

\frac{s ^{3}}{s ^{- 2}} : s^{5}

= \frac{s ^{5} j ^{9}}{4 ^{4} \cdot 5}

4^{4} \cdot 5 = 1280

= \frac{s ^{5} j ^{9}}{1280}

lo g_{6} (30) - lo g_{6} (5)

x^{2} (x + 1)^{3}

- 5 - 9

(11 - 12 i) - (10 + 9 i)

1 - \frac{x ^{2}}{4}

What is ((4s^{-1}j^{-3})^{-3})/(20s^{-2)} ?
The solution to ((4s^{-1}j^{-3})^{-3})/(20s^{-2)} is (s^5j^9)/(1280)