What is 56<7x-7(((x-8))/2)<= 112 ?

The solution to 56<7x-7(((x-8))/2)<= 112 is 8<x<= 24

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56<7x-7(((x-8))/2)<= 112

56 < 7 x - 7 (\frac{( x - 8 )}{2}) \leq 112

8 < x \leq 24

Interval Notation

(8, 24]

Solution steps

56 < 7 x - 7 (\frac{( x - 8 )}{2}) \leq 112

a < u \leq b

then

a < u and u \leq b

56 < 7 x - 7 (\frac{( x - 8 )}{2}) and 7 x - 7 (\frac{( x - 8 )}{2}) \leq 112

56 < 7 x - 7 \cdot \frac{x - 8}{2} : x > 8

7 x - 7 \cdot \frac{x - 8}{2} \leq 112 : x \leq 24

Combine the intervals

x > 8 and x \leq 24

Merge Overlapping Intervals

8 < x \leq 24

6 y < 18

a^{8} - b^{8}

5 x^{2} + 9 = 4 x + 5

3 (k - 2) - 6 = 4 k - (3 k - 1)

- (\frac{2}{3})^{3}

What is 56<7x-7(((x-8))/2)<= 112 ?
The solution to 56<7x-7(((x-8))/2)<= 112 is 8<x<= 24