What is (y^2+2y-3)/(y^2-3y-18)*(4y^2-24y)/(2y^2-2y) ?

The solution to (y^2+2y-3)/(y^2-3y-18)*(4y^2-24y)/(2y^2-2y) is 2

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simplify (y^2+2y-3)/(y^2-3y-18)*(4y^2-24y)/(2y^2-2y)

simplify

\frac{y ^{2} + 2 y - 3}{y ^{2} - 3 y - 18} \cdot \frac{4 y ^{2} - 24 y}{2 y ^{2} - 2 y}

2

Solution steps

\frac{y ^{2} + 2 y - 3}{y ^{2} - 3 y - 18} \cdot \frac{4 y ^{2} - 24 y}{2 y ^{2} - 2 y}

Cancel

\frac{y ^{2} + 2 y - 3}{y ^{2} - 3 y - 18} : \frac{y - 1}{y - 6}

= \frac{y - 1}{y - 6} \cdot \frac{4 y ^{2} - 24 y}{2 y ^{2} - 2 y}

Cancel

\frac{4 y ^{2} - 24 y}{2 y ^{2} - 2 y} : \frac{2 ( y - 6 )}{y - 1}

= \frac{y - 1}{y - 6} \cdot \frac{2 ( y - 6 )}{y - 1}

Cross-cancel common factor:

y - 1

= \frac{2 ( y - 6 )}{y - 6}

Cancel the common factor:

y - 6

= 2

\frac{29}{6}

(7 - 8 i) + (- 12 - 4 i)

(2 x^{3} + 5 x - 3) + (2 x^{3} - 3 x^{2} + 4 x)

\frac{42 x ^{9} y ^{2}}{- 7 x ^{5} y ^{2}}

\frac{24}{72}

What is (y^2+2y-3)/(y^2-3y-18)*(4y^2-24y)/(2y^2-2y) ?
The solution to (y^2+2y-3)/(y^2-3y-18)*(4y^2-24y)/(2y^2-2y) is 2