What is (2^{-3}+3^{-2})/(2^{-2)} ?

The solution to (2^{-3}+3^{-2})/(2^{-2)} is 17/18

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simplify (2^{-3}+3^{-2})/(2^{-2)}

simplify

\frac{2 ^{- 3} + 3 ^{- 2}}{2 ^{- 2}}

\frac{17}{18}

Decimal Notation

0.94444 \dots

Solution steps

\frac{2 ^{- 3} + 3 ^{- 2}}{2 ^{- 2}}

Simplify

2^{- 3} + 3^{- 2} : \frac{17}{72}

= \frac{\frac{17}{72}}{2 ^{- 2}}

Apply the fraction rule:

\frac{\frac{a}{b}}{c} = \frac{a}{b \cdot c}

= \frac{17}{72 \cdot 2 ^{- 2}}

Simplify

72 \cdot 2^{- 2} : 18

= \frac{17}{18}

\frac{( x ^{2} + 6 x + 8 )}{( x + 2 )}

\frac{27}{15}

- \frac{4}{3} - 2

- 463 + 1028

\frac{\frac{2}{5} + \frac{1}{2} - \frac{3}{4}}{\frac{1}{3}}

What is (2^{-3}+3^{-2})/(2^{-2)} ?
The solution to (2^{-3}+3^{-2})/(2^{-2)} is 17/18